A. The net force on the object is zero.

B. The acceleration of the object is in the forward direction.

C. The net force on the object is in the forward direction.

D. No forces are acting on the object.

A. equal to the weight of the brick

B. less than the weight of the brick

C. greater than the weight of the brick

D. zero

Ay = 4.6 m

Explanation:

<-6.1,-2.2>

<2.2,-6.9>

________________

<-8.3, 4.7>

sqrt(((-8.3)^2)+((4.7)^2)) = 9.5

a=F/m

a. Gravity and kinetic friction

b. Gravity and a normal force

c. Gravity and the force of the push

d. Gravity, a normal force, and kinetic friction

e. Gravity, a normal force, kinetic friction, and the force of the push

A. The rope tension is greater than the object’s weight.

B. The rope tension equals the object’s weight.

C. The rope tension is less than the object’s weight.

D. The rope tension can’t be compared to the object’s weight.

A. The rope tension is greater than the object’s weight.

B. The rope tension equals the object’s weight.

C. The rope tension is less than the object’s weight.

D. The rope tension can’t be compared to the object’s weight.

Small static friction force in the -x direction.

Equal Tension and Kinetic friction

constant speed. Which is the

correct free-body diagram?

A. greater than the force of Sarah on Jack.

B. equal to the force of Sarah on Jack.

C. less than the force of Sarah on Jack.

A. The mosquito exerts more force on the truck than the truck exerts on the mosquito.

B. The truck exerts more force on the mosquito than the mosquito exerts on the truck.

C. The mosquito exerts the same force on the truck as the truck exerts on the mosquito.

D. The truck exerts a force on the mosquito but the mosquito does not exert a force on the truck.

E. The mosquito exerts a force on the truck but the truck does not exert a force on the mosquito.

A. Greater than your true weight.

B. Equal to your true weight.

C. Less than your true weight.

A. Smaller than the coefficient of kinetic friction.

B. Equal to the coefficient of kinetic friction.

C. Greater than the coefficient of kinetic friction.

A. The drag force increases.

B. The drag force stays the same.

C. The drag force decreases.

A. 25N

B. 50N

C. 100N

D. 200N

Neither force has an x-component, so we need to examine only the y-components of the forces. In this case, the y-component of Newton’s second law is

1. Sigma(Fy) = Ty + wy = may = 0

2. T – w = 0

3. T = w = 500 N

Tension in the rope equals the weight of the orangutan.

Then use Vf = Vi + ay(Change in T)